How to make a hangman game in java

Hello what's going on, it's me Ronaldo, and thanks again for taking the time to view this blog, I hope you are doing right, Within this article I will be showing you, how to code The "HANGMAN GAME" in java. so this is another version other than the hangman game you've found on the net. so these version is originally a word guessing without using any visual graphics on the UI (User Interface), once you hit the letter of masked words... then literally it will be revealed. So the code below is which you can test or experiment on your preferred IDE. Enjoy!!!

import java.util.Arrays;
import java.util.Scanner;
public class Hangman{
public static void main(String[] args) {
String[] words = {"writer", "that", "program"};
// Pick random index of words array
int randomWordNumber = (int) (Math.random() * words.length);
// Create an array to store already entered letters
char[] enteredLetters = new char[words[randomWordNumber].length()];
int triesCount = 0;
boolean wordIsGuessed = false;
do {
// infinitely iterate through cycle as long as enterLetter returns true
// if enterLetter returns false that means user guessed all the letters
// in the word e. g. no asterisks were printed by printWord
switch (enterLetter(words[randomWordNumber], enteredLetters)) {
case 0:
triesCount++;
break;
case 1:
triesCount++;
break;
case 2:
break;
case 3:
wordIsGuessed = true;
break;
}
}
 while (! wordIsGuessed);
System.out.println("\nThe word is " + words[randomWordNumber] +
" You missed " + (triesCount -findEmptyPosition(enteredLetters)) +
" time(s)");
}
/* Hint user to enter a guess letter,
returns 0 if letter entered is not in the word (counts as try),
returns 1 if letter were entered 1st time (counts as try),
returns 2 if already guessed letter was REentered,
returns 3 if all letters were guessed */
public static int enterLetter(String word, char[] enteredLetters) {
System.out.print("(Guess) Enter a letter in word ");
// If-clause is true if no asterisks were printed so
// word is successfully guessed
if (! printWord(word, enteredLetters))
return 3;
System.out.print(" > ");
Scanner input = new Scanner(System.in);
int emptyPosition = findEmptyPosition(enteredLetters);
char userInput = input.nextLine().charAt(0);
if (inEnteredLetters(userInput, enteredLetters)) {
System.out.println(userInput + " is already in the word");
return 2;
}
else if (word.contains(String.valueOf(userInput))) {
enteredLetters[emptyPosition] = userInput;
return 1;
}
else {
System.out.println(userInput + " is not in the word");
return 0;
}
}
/* Print word with asterisks for hidden letters, returns true if
asterisks were printed, otherwise return false */
public static boolean printWord(String word, char[] enteredLetters) {
// Iterate through all letters in word
boolean asteriskPrinted = false;
for (int i = 0; i < word.length(); i++) {
char letter = word.charAt(i);
// Check if letter already have been entered bu user before
if (inEnteredLetters(letter, enteredLetters))
System.out.print(letter); // If yes - print it
else {
System.out.print('*');
asteriskPrinted = true;
}
}
return asteriskPrinted;
}
/* Check if letter is in enteredLetters array */
public static boolean inEnteredLetters(char letter, char[] enteredLetters) {
return new String(enteredLetters).contains(String.valueOf(letter));
}
/* Find first empty position in array of entered letters (one with code \u0000) */
public static int findEmptyPosition(char[] enteredLetters) {
int i = 0;
while (enteredLetters[i] != '\u0000') i++;
return i;
}
}